leetcode/0567_permutation-in-string/python3/hashmaps_in_loop.py

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Python
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2022-04-24 14:06:05 +00:00
# Time: O(S1 · S2) ; S2 is len(s1) and S2 is len(S2)
# Space: O(S2 · 26)
from collections import Counter
class Solution:
def checkInclusion(self, s1: str, s2: str) -> bool:
if len(s1) > len(s2): return False
if len(s1) == len(s2):
return Counter(s1) == Counter(s2)
s1_counter = Counter(s1)
target_length = len(s1)
end = target_length - 1
while end < len(s2):
start = end - target_length + 1
curr_substring = s2[start:end + 1]
# Check if counters match for the given substring
# indicated by start:end with a length of target_length
if s1_counter == Counter(curr_substring):
return True
end += 1
return False