40 lines
1018 B
Markdown
40 lines
1018 B
Markdown
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Given a 2D `grid` of size `m x n` and an integer `k`. You need to shift the `grid` `k` times.
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In one shift operation:
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* Element at `grid[i][j]` moves to `grid[i][j + 1]`.
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* Element at `grid[i][n - 1]` moves to `grid[i + 1][0]`.
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* Element at `grid[m - 1][n - 1]` moves to `grid[0][0]`.
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Return the _2D grid_ after applying shift operation `k` times.
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**Example 1:**
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![](https://assets.leetcode.com/uploads/2019/11/05/e1.png)
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Input: grid = [[1,2,3],[4,5,6],[7,8,9]], k = 1
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Output: [[9,1,2],[3,4,5],[6,7,8]]
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**Example 2:**
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![](https://assets.leetcode.com/uploads/2019/11/05/e2.png)
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Input: grid = [[3,8,1,9],[19,7,2,5],[4,6,11,10],[12,0,21,13]], k = 4
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Output: [[12,0,21,13],[3,8,1,9],[19,7,2,5],[4,6,11,10]]
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**Example 3:**
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Input: grid = [[1,2,3],[4,5,6],[7,8,9]], k = 9
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Output: [[1,2,3],[4,5,6],[7,8,9]]
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**Constraints:**
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* `m == grid.length`
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* `n == grid[i].length`
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* `1 <= m <= 50`
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* `1 <= n <= 50`
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* `-1000 <= grid[i][j] <= 1000`
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* `0 <= k <= 100`
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