14 lines
387 B
Python
14 lines
387 B
Python
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# Time: O(N * MlogM) where N is len(strs) and M is num of chars in a string
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# Space: O(N)
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class Solution:
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def groupAnagrams(self, strs: List[str]) -> List[List[str]]:
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groups = {}
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for s in strs:
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s_sorted = ''.join(sorted(s))
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groups[s_sorted] = groups.get(s_sorted, []) + [s]
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return list(groups.values())
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