better soln
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# Time: O(N)
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# Space: O(N)
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class Solution:
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def longestConsecutive(self, nums: List[int]) -> int:
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visited = {}
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for _, num in enumerate(nums):
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visited[num] = False
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maxl = 0
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for _, num in enumerate(nums):
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if visited[num]:
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continue
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l = 1
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prev = num - 1
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while prev in visited:
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visited[prev] = True
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l += 1
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prev -= 1
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next = num + 1
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while next in visited:
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visited[next] = True
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l += 1
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next += 1
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maxl = max(maxl, l)
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return maxl
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