feat(392-is-subsequence): simplify and add golang soln

0392_is-subsequence/golang/main.go

@@ -0,0 +1,21 @@
+func isSubsequence(s string, t string) bool {
+	slen, tlen, si, ti := len(s), len(t), 0, 0
+
+	if slen == 0 {
+		return true
+	}
+
+	if slen > tlen {
+		return false
+	}
+
+	for ti < tlen && si < slen {
+		if s[si] == t[ti] {
+			si += 1
+		}
+
+		ti += 1
+	}
+
+	return si == slen
+}

0392_is-subsequence/python3/main.py

@@ -1,9 +1,6 @@
 class Solution:
     def isSubsequence(self, s: str, t: str) -> bool:
-        slen = len(s)
+        slen, tlen, si, ti = len(s), len(t), 0, 0
-        tlen = len(t)
-        si = 0
-        ti = 0
         
         # If s is longer than t, it's obviously not
         # going to be a subsequence
@@ -11,27 +8,9 @@ class Solution:
             return False
         
         while ti < tlen and si < slen:
-            found = False
-            
-            while ti < tlen:
             if s[si] == t[ti]:
-                    found = True
-                    ti += 1
-                    break
-
-                ti += 1
-            
-            if not found:
-                return False
-            
                 si += 1
             
-        # We reached end of t but we still have
+            ti += 1
-        # characters remaining in s and hence
-        # it's not a subsequence
-        if si < slen:
-            return False
-            
-        return True
-        
 
+        return si == slen