single-number py3

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Sangeeth Sudheer 2022-04-26 02:26:40 +05:30
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Given a **non-empty** array of integers `nums`, every element appears _twice_ except for one. Find that single one.
You must implement a solution with a linear runtime complexity and use only constant extra space.
**Example 1:**
Input: nums = [2,2,1]
Output: 1
**Example 2:**
Input: nums = [4,1,2,1,2]
Output: 4
**Example 3:**
Input: nums = [1]
Output: 1
**Constraints:**
* `1 <= nums.length <= 3 * 104`
* `-3 * 104 <= nums[i] <= 3 * 104`
* Each element in the array appears twice except for one element which appears only once.
https://leetcode.com/problems/single-number/

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from functools import reduce
class Solution:
def singleNumber(self, nums: List[int]) -> int:
return reduce(lambda r, a: r ^ a, nums)