feat(1-two-sum): add README
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0001_two-sum/README.md
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0001_two-sum/README.md
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Given an array of integers `nums` and an integer `target`, return *indices of the two numbers such that they add up to `target`*.
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You may assume that each input would have *exactly* one solution, and you may not use the *same* element twice.
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You can return the answer in any order.
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Example 1:
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```
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Input: nums = [2,7,11,15], target = 9
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Output: [0,1]
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Output: Because nums[0] + nums[1] == 9, we return [0, 1].
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```
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Example 2:
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```
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Input: nums = [3,2,4], target = 6
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Output: [1,2]
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```
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Example 3:
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```
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Input: nums = [3,3], target = 6
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Output: [0,1]
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```
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Constraints:
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- `2 <= nums.length <= 104`
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- `-109 <= nums[i] <= 109`
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- `-109 <= target <= 109`
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- Only one valid answer exists.
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Follow-up: Can you come up with an algorithm that is less than `O(n2) `time complexity?
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