maximum-depth-of-bt py3

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Sangeeth Sudheer 2022-04-25 11:30:32 +05:30
parent e793d395bd
commit 713154644b
5 changed files with 68 additions and 0 deletions

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Given the `root` of a binary tree, return _its maximum depth_.
A binary tree's **maximum depth** is the number of nodes along the longest path from the root node down to the farthest leaf node.
**Example 1:**
![](https://assets.leetcode.com/uploads/2020/11/26/tmp-tree.jpg)
Input: root = [3,9,20,null,null,15,7]
Output: 3
**Example 2:**
Input: root = [1,null,2]
Output: 2
**Constraints:**
* The number of nodes in the tree is in the range `[0, 104]`.
* `-100 <= Node.val <= 100`
https://leetcode.com/problems/maximum-depth-of-binary-tree

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# Time: O(N)
# Space: O(N)
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
maxDepthValue = 0
def maxDepth(self, root: Optional[TreeNode]) -> int:
'''
Recursive DFS pre-order but storing max globally
'''
def findMax(node, depth):
if node is None: return None
currDepth = depth + 1
self.maxDepthValue = max(currDepth, self.maxDepthValue)
findMax(node.left, currDepth)
findMax(node.right, currDepth)
findMax(root, 0)
return self.maxDepthValue

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# Time: O(N)
# Space: O(N)
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
maxDepthValue = 0
def maxDepth(self, root: Optional[TreeNode]) -> int:
'''
Recursive DFS
'''
return 0 if root is None else 1 + max(self.maxDepth(root.left), self.maxDepth(root.right))