top-travellers sql

This commit is contained in:
Sangeeth Sudheer 2022-04-28 00:36:11 +05:30
parent 950abb6b37
commit ce4608aa34
3 changed files with 85 additions and 1 deletions

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@ -4,7 +4,7 @@ import Turndown from "turndown";
import * as cheerio from "cheerio"; import * as cheerio from "cheerio";
import { client, gql } from "./graphql.mjs"; import { client, gql } from "./graphql.mjs";
const langExt = { python3: "py", nodejs: "js", cpp: "cpp" }; const langExt = { python3: "py", nodejs: "js", cpp: "cpp", sql: "sql" };
const link = await question("Enter leetcode problem link: "); const link = await question("Enter leetcode problem link: ");
const titleSlug = path.basename(new URL(link).pathname); const titleSlug = path.basename(new URL(link).pathname);

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@ -0,0 +1,78 @@
Table: `Users`
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| id | int |
| name | varchar |
+---------------+---------+
id is the primary key for this table.
name is the name of the user.
Table: `Rides`
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| id | int |
| user_id | int |
| distance | int |
+---------------+---------+
id is the primary key for this table.
user_id is the id of the user who traveled the distance "distance".
Write an SQL query to report the distance traveled by each user.
Return the result table ordered by `travelled_distance` in **descending order**, if two or more users traveled the same distance, order them by their `name` in **ascending order**.
The query result format is in the following example.
**Example 1:**
Input:
Users table:
+------+-----------+
| id | name |
+------+-----------+
| 1 | Alice |
| 2 | Bob |
| 3 | Alex |
| 4 | Donald |
| 7 | Lee |
| 13 | Jonathan |
| 19 | Elvis |
+------+-----------+
Rides table:
+------+----------+----------+
| id | user_id | distance |
+------+----------+----------+
| 1 | 1 | 120 |
| 2 | 2 | 317 |
| 3 | 3 | 222 |
| 4 | 7 | 100 |
| 5 | 13 | 312 |
| 6 | 19 | 50 |
| 7 | 7 | 120 |
| 8 | 19 | 400 |
| 9 | 7 | 230 |
+------+----------+----------+
Output:
+----------+--------------------+
| name | travelled_distance |
+----------+--------------------+
| Elvis | 450 |
| Lee | 450 |
| Bob | 317 |
| Jonathan | 312 |
| Alex | 222 |
| Alice | 120 |
| Donald | 0 |
+----------+--------------------+
Explanation:
Elvis and Lee traveled 450 miles, Elvis is the top traveler as his name is alphabetically smaller than Lee.
Bob, Jonathan, Alex, and Alice have only one ride and we just order them by the total distances of the ride.
Donald did not have any rides, the distance traveled by him is 0.
https://leetcode.com/problems/top-travellers/

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# Write your MySQL query statement below
SELECT Users.name as name, COALESCE(SUM(distance), 0) as travelled_distance
FROM Users
LEFT JOIN Rides ON Users.id = Rides.user_id
GROUP BY Users.id
ORDER BY travelled_distance DESC, name ASC;