feat(189-rotate-array): add py3 solution

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Sangeeth Sudheer 2022-04-04 22:30:14 +05:30
parent eb41db0efa
commit da5d790d16
3 changed files with 47 additions and 0 deletions

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Given an array, rotate the array to the right by `k` steps, where `k` is non-negative.
**Example 1:**
Input: nums = [1,2,3,4,5,6,7], k = 3
Output: [5,6,7,1,2,3,4]
Explanation:
rotate 1 steps to the right: [7,1,2,3,4,5,6]
rotate 2 steps to the right: [6,7,1,2,3,4,5]
rotate 3 steps to the right: [5,6,7,1,2,3,4]
**Example 2:**
Input: nums = [-1,-100,3,99], k = 2
Output: [3,99,-1,-100]
Explanation:
rotate 1 steps to the right: [99,-1,-100,3]
rotate 2 steps to the right: [3,99,-1,-100]
**Constraints:**
* `1 <= nums.length <= 105`
* `-231 <= nums[i] <= 231 - 1`
* `0 <= k <= 105`
**Follow up:**
* Try to come up with as many solutions as you can. There are at least **three** different ways to solve this problem.
* Could you do it in-place with `O(1)` extra space?

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# Time: O(N)
# Space: O(N)
class Solution:
def rotate(self, nums: List[int], k: int) -> None:
"""
Do not return anything, modify nums in-place instead.
"""
n = len(nums)
result = [None] * n
for i, num in enumerate(nums):
new_i = (i + k) % n
result[new_i] = num
for i, num in enumerate(nums):
nums[i] = result[i]

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