leetcode/0783_search-in-a-binary-sea...
Sangeeth Sudheer 27ed30d2a9 feat(0783_search-in-a-binary-search-tree): add python3 soln 2022-04-05 21:47:41 +05:30
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python3 feat(0783_search-in-a-binary-search-tree): add python3 soln 2022-04-05 21:47:41 +05:30
README.md feat(0783_search-in-a-binary-search-tree): add python3 soln 2022-04-05 21:47:41 +05:30

README.md

You are given the root of a binary search tree (BST) and an integer val.

Find the node in the BST that the node's value equals val and return the subtree rooted with that node. If such a node does not exist, return null.

Example 1:

Input: root = [4,2,7,1,3], val = 2
Output: [2,1,3]

Example 2:

Input: root = [4,2,7,1,3], val = 5
Output: []

Constraints:

  • The number of nodes in the tree is in the range [1, 5000].
  • 1 <= Node.val <= 107
  • root is a binary search tree.
  • 1 <= val <= 107