leetcode/0792_binary-search
Sangeeth Sudheer 2b889c6f89 feat(792-binary-search): add py3 solution 2022-04-02 15:39:31 +05:30
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python3 feat(792-binary-search): add py3 solution 2022-04-02 15:39:31 +05:30
README.md feat(792-binary-search): add py3 solution 2022-04-02 15:39:31 +05:30

README.md

Given an array of integers nums which is sorted in ascending order, and an integer target, write a function to search target in nums. If target exists, then return its index. Otherwise, return -1.

You must write an algorithm with O(log n) runtime complexity.

Example 1:

**Input:** nums = \[-1,0,3,5,9,12\], target = 9
**Output:** 4
**Explanation:** 9 exists in nums and its index is 4

Example 2:

**Input:** nums = \[-1,0,3,5,9,12\], target = 2
**Output:** -1
**Explanation:** 2 does not exist in nums so return -1

Constraints:

  • 1 <= nums.length <= 104
  • -104 < nums[i], target < 104
  • All the integers in nums are unique.
  • nums is sorted in ascending order.