40 lines
1.2 KiB
Python
40 lines
1.2 KiB
Python
class Solution:
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def findUnsortedSubarray(self, nums: List[int]) -> int:
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min_unsorted = float("inf")
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max_unsorted = float("-inf")
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# Find min and max element in the unsorted portion
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for i, num in enumerate(nums):
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if not self.is_sorted(i, nums):
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min_unsorted = min(min_unsorted, num)
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max_unsorted = max(max_unsorted, num)
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if min_unsorted == float("inf"):
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return 0
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# Find right places for min and max elements from previous
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# step in the "sorted" section of the array
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left = 0
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while nums[left] <= min_unsorted:
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left += 1
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right = len(nums) - 1
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while nums[right] >= max_unsorted:
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right -= 1
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return right - left + 1
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def is_sorted(self, i: int, nums: List[int]) -> bool:
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n = len(nums)
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if n <= 1:
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return True
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if i == 0:
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return nums[i] <= nums[i + 1]
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if i == n - 1:
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return nums[i - 1] <= nums[i]
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return nums[i - 1] <= nums[i] <= nums[i + 1]
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