33 lines
1.1 KiB
Markdown
33 lines
1.1 KiB
Markdown
You are given the `root` node of a binary search tree (BST) and a `value` to insert into the tree. Return _the root node of the BST after the insertion_. It is **guaranteed** that the new value does not exist in the original BST.
|
||
|
||
**Notice** that there may exist multiple valid ways for the insertion, as long as the tree remains a BST after insertion. You can return **any of them**.
|
||
|
||
**Example 1:**
|
||
|
||
|
||
|
||
Input: root = [4,2,7,1,3], val = 5
|
||
Output: [4,2,7,1,3,5]
|
||
Explanation: Another accepted tree is:
|
||
|
||
|
||
|
||
**Example 2:**
|
||
|
||
Input: root = [40,20,60,10,30,50,70], val = 25
|
||
Output: [40,20,60,10,30,50,70,null,null,25]
|
||
|
||
|
||
**Example 3:**
|
||
|
||
Input: root = [4,2,7,1,3,null,null,null,null,null,null], val = 5
|
||
Output: [4,2,7,1,3,5]
|
||
|
||
|
||
**Constraints:**
|
||
|
||
* The number of nodes in the tree will be in the range `[0, 104]`.
|
||
* `-108 <= Node.val <= 108`
|
||
* All the values `Node.val` are **unique**.
|
||
* `-108 <= val <= 108`
|
||
* It's **guaranteed** that `val` does not exist in the original BST. |